MinAvgTwoSlice

Find the minimal average of any slice containing at least two elements.

A non-empty array A consisting of N integers is given. A pair of integers (P, Q), such that 0 ≤ P < Q < N, is called a slice of array A (notice that the slice contains at least two elements). The average of a slice (P, Q) is the sum of A[P] + A[P + 1] + ... + A[Q] divided by the length of the slice. To be precise, the average equals (A[P] + A[P + 1] + ... + A[Q]) / (Q − P + 1).

For example, array A such that:

A[0] = 4
A[1] = 2
A[2] = 2
A[3] = 5
A[4] = 1
A[5] = 5
A[6] = 8

contains the following example slices:

slice (1, 2), whose average is (2 + 2) / 2 = 2; slice (3, 4), whose average is (5 + 1) / 2 = 3; slice (1, 4), whose average is (2 + 2 + 5 + 1) / 4 = 2.5. The goal is to find the starting position of a slice whose average is minimal.

Write a function:

func Solution(A []int) int

that, given a non-empty array A consisting of N integers, returns the starting position of the slice with the minimal average. If there is more than one slice with a minimal average, you should return the smallest starting position of such a slice.

For example, given array A such that:

A[0] = 4
A[1] = 2
A[2] = 2
A[3] = 5
A[4] = 1
A[5] = 5
A[6] = 8

the function should return 1, as explained above.

Write an efficient algorithm for the following assumptions:

N is an integer within the range [2..100,000]; each element of array A is an integer within the range [−10,000..10,000]. Copyright 2009–2021 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.

題目大意

找出array兩index中平均值最小 ,並回傳start的 index

解題思路

最小avg的slice(n,m),m-n+1一定是2或者3,也就是這個最小avg的slice由2個或者3個元素組成 因為題目中說明 0 因此可以得出2個或者3個元素是最小的組合,比如length=3的數組,你無法一次分出2個slice,length=2的數組也一樣。為什麼要這麼去想呢?因為你要“比較”出最小的avg,怎麼才能"比較"?那就是必須一次至少有2個slice才能相互比較。那麼當N>=4時,我們就能一次最少分出2個slice

來源

解答

https://github.com/kimi0230/LeetcodeGolang/blob/master/Codility/Lesson/0005.Prefix-Sums/MinAvgTwoSlice/MinAvgTwoSlice.go

package MinAvgTwoSlice

import "math"

func Solution(A []int) int {

    min := math.MaxFloat64
    minIndex := -1
    for i := 0; i < len(A)-1; i++ {
        // 2個數平均
        if i+1 < len(A) {
            tmp := (float64(A[i]) + float64(A[i+1])) / float64(2)
            if tmp < min {
                min = tmp
                minIndex = i
            }
        }
        // 3個數平均
        if i+2 < len(A) {
            tmp := (float64(A[i]) + float64(A[i+1]) + float64(A[i+2])) / float64(3)
            if tmp < min {
                min = tmp
                minIndex = i
            }
        }
    }

    return minIndex
}
© Kimi Tsai all right reserved.            Updated : 2024-05-06 09:36:37

results matching ""

    No results matching ""